Holooly Plus Logo

Question 13.14: Applying Le Châtelier’s Principle to Pressure and Volume Cha......

Applying Le Châtelier’s Principle to Pressure and Volume Changes

Does the number of moles of reaction products increase, decrease, or remain the same when each of the following equilibria is subjected to a decrease in pressure by increasing the volume?

(a) \mathrm{PCl}_5(g) \rightleftharpoons \mathrm{PCl}_3(g)+\mathrm{Cl}_2(g)

(b) \mathrm{CaO}(s)+\mathrm{CO}_2(g) \rightleftharpoons \mathrm{CaCO}_3(s)

(c) 3 \mathrm{Fe}(s)+4 \mathrm{H}_2 \mathrm{O}(g) \rightleftharpoons \mathrm{Fe}_3 \mathrm{O}_4(s)+4 \mathrm{H}_2(g)

STRATEGY

According to Le Châtelier’s principle, the stress of a decrease in pressure is relieved by net reaction in the direction that increases the number of moles of gas.

Step-by-Step
The 'Blue Check Mark' means that this solution was answered by an expert.
Learn more on how do we answer questions.

(a) Because the forward reaction converts 1 mol of gas to 2 mol of gas, net reaction will go from reactants to products, thus increasing the number of moles of PCl_3 and Cl_2.

(b) Because there is 1 mol of gas on the reactant side of the balanced equation and none on the product side, the stress of a decrease in pressure is relieved by net reaction from products to reactants. The number of moles of CaCO_3 therefore decreases.

(c) Because there are 4 mol of gas on both sides of the balanced equation, the composition of the equilibrium mixture is unaffected by a change in pressure. The number of moles of Fe_3O_4 and H_2 remains the same.

Related Answered Questions