Convert the following expression into the standard SOP form.

F=A+\bar{B} CStep-by-Step

Learn more on how do we answer questions.

The domain of this SOP expression is made up of A, B, and C.

In the first term, A, the other two variables B and C are absent. So the first term is multiplied by B+\bar{B} and C+\bar{C}as below:

A=A(B+\bar{B})(C+\bar{C} ) = ABC+AB\bar{C}+A\bar{B}C+A\bar{B}\bar{C}In the second term, BC, the variable A is absent. So the second term is multiplied by A+\bar{A} as below:

\bar{B} C=\bar{B} C(A+\bar{A} )+A\bar{B} C+\bar{A} \bar{B} CThe standard SOP form of the original expression is as follows:

F=A+\bar{B} C=ABC+AB\bar{C} +A\bar{B} C+A\bar{B} \bar{C} +\bar{A} \bar{B} C=m_{1} +m_{4} +m_{5}+m_{6}+m_{7}=\sum{m(1,4,5,6,7)}where two same standard product terms A\bar{B}C can be merged by using rule 7: A+A = A.

Question: 3.16

The given SOP expression has a domain of four vari...

Question: 3.18

Map the SOP expression on a 4-variable Karnaugh ma...

Question: 3.15

The given SOP expression has a domain of three var...

Question: 3.14

According to the rules of grouping 1s, the result ...

Question: 3.13

The given SOP expression has a domain of four vari...

Question: 3.12

One method is to convert this nonstandard SOP expr...

Question: 3.11

The given SOP expression has a domain of three var...

Question: 3.10

F=A\bar{ B}+B \bar{C}+\bar{B} C+\bar{A} B[/...

Question: 3.5

There are five 1s in the output column and the cor...

Question: 3.4

Step 1 There are three variables in the domain, so...