## Chapter 1

## Q. 1.P.9

Determine the current through the 5 Ω resistor in the following figure.

## Step-by-Step

## Verified Solution

Consider the following equivalent circuit

Since there is violation of the KVL in the network, the circuit connection is physically not possible.

Applying KVL, we get

5 – 10 = 0 ⇒ −5 = 0

which is not possible.

Now consider the following equivalent circuit

Here applying KVL, we get

10 + 10 = 0 ⇒ 20 = 0

It is also violation of KVL, so physically not possible.

The value of current can be determined using the following circuit.

The voltage at 5 Ω resistor is V_{5 \Omega}=10 V , therefore current is

I_{5 \Omega}=\frac{10}{5}=2 A