## Q. 1.P.15

Determine the current through the ideal diode (D) in the following circuit.

## Verified Solution

Since the diode is a non-linear element, the network is non-linear and hence only source transformation is applicable (superposition theorem is not applicable).

For an ideal diode $V_{ f }=0 \text { and } R_{ f }=0$. So,

$5 – 2 i_d – 1 i_d – 2 = 0 ⇒ i_d = 1 A$