# Question 11.3: For the four diode gate shown in Fig. 11.21(a), Vs = 20 V, R......

For the four diode gate shown in Fig. 11.21(a),$\ V_{s}$ = 20 V,$\ R_{L}$ = 200 kΩ ,$\ R_{C}$ = 100 kΩ,$\ R_{f}$ = 0.5 kΩ,$\ R = R_{s}$ = 1 kΩ. Find$\ V_{n(min)}$, A and$\ V_{C(min)}$.

Step-by-Step
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(i) From Eq. (11.17),

$\ V_{n(min)} = V_{s}$ = 20 V              (11.17)

(ii) From Eq. (11.15),

$\ V_{C(min)} = V_{S} \left(2 + \frac{R_{C}}{R_{L}} \right) \left(1 + \frac{R}{4 R_{f}} \right) \thickapprox V_{S} \left(2 + \frac{R_{C}}{R_{L}} \right)$                        (11.15)

$\ V_{C(min)} = V_{S} \left(2 + \frac{R_{C}}{R_{L}} \right) \left(1 + \frac{R}{4 R_{f}} \right)$

$\ = 20 \left(2 + \frac{100}{200} \right) \left(1 + \frac{1}{2} \right)$ = 20 × 2.5 × 1.5 = 75 V

(iii) From Eq. (11.16),

$\ A = \frac{1}{1 + \frac{1}{R_{L}} \left(R_{S} + R_{f} + \frac{R}{4}\right) + \frac{1}{R_{C}}\left(2R_{S} + R_{f} + \frac{R}{2}\right) \left( 1 + \frac{R_{f}}{2R_{L}} \right) }$              (11.16)

$\ A = \frac{1}{1 + \frac{1 + 0.5 + 0.25 }{200} \left( \frac{2 + 0.5 + 0.5}{100}\right) \left( 1 + \frac{0.5}{400}\right) }$

$\ = \frac{1}{ 1 + 0.00875 + 0.03}$ = 0.963

A = 0.963

Question: 11.1

## In the circuit shown in Fig. 11.16(a), RL = R1 = 100 kΩ , R2 = 50 kΩ and the signal has a peak value of 20 V. Find (a) A (b) VC(min) (c) Vn(min) (d) Ri when the diodes are ON ...

(a) \ A = \frac{a}{1 + a\frac{R_{1}}{2R_{L}...
Question: 11.2

## For the four-diode gate shown in Fig. 11.20(a), RL = R2 = 100 kΩ and R1 = 1 kΩ, Rf = 25 Ω, Vs = 20 V. Calculate (a) A (b) V(min) (c) VC(min) (d) Vn(min) for V = V(min) ...

(a) We have: \ R = \frac{R_{1}R_{2}}{R_{1} ...
Question: 11.4

## Consider the following situation in the FET series gate, Vs = ± 2 V, Rs = 100 Ω, RL = 10 kΩ. The FET has the following parameters: VGS(OFF)max = −10 V and RD(ON) = 20 Ω. Calculate the voltage levels of the control signal, ID, error due to RS and error due to RD(ON). ...

The control signal should have a value\ V_{...
Question: 11.5

## In the circuit shown in Fig. 11.16(a), RL = R1 = 200 kΩ, R2 = 100 kΩ and the signal has a peak value of 10 V. Find (a) A (b) VC(min) (c) Vn(min) (d) Ri ...

(a) \ A = \frac{α}{1 + α(R_{1}/2R_{L})}[/la...
Question: 11.6

## For the four-diode gate shown in Fig 11.20(a), RL = R2 = 50 kΩ and R1 = 1 kΩ, Rf = 25 Ω, Vs = 10 V. Calculate (a) A (b) V(min) (c) VC(min) (d) for V = V(min) ...

(a) We have \ R = \frac{R_{2}R_{1}}{R_{2} +...
The control signal should have a value\ V_{...