From the drain characteristics of Fig. 4-9(b), we see that V_T = 4 \text{V} and that I_{D\text{on}} = 5 \text{mA} at V_{GSon} = 8 \text{V}. Thus,
I_{DQ} = I_{D\text{on}} \left(1 – \frac{V_{GSQ}}{V_T} \right)^2 = 5 × 10^{-3} \left(1 – \frac{6.90}{4} \right)^2 = 2.63 \text{mA}
(Compare Example 4.5.)