Gate current is negligible for the p-channel JFET of Fig. 4-17. If V_{DD} = -20 \text{V}, I_{DSS} = -10 \text{mA}, I_{DQ} = -8 \text{mA}, V_{p0} = -4 \text{V}, R_S = 0, and R_D = 1.5 kΩ, find (a) V_{GG} and (b) V_{DSQ}.
(a) Solving (4.2) for v_{GS} and substituting Q-point conditions yield
i_D = I_{DSS} \left( 1 + \frac{v_{GS}}{V_{p0}} \right)^2 (4.2)
V_{GSQ} = V_{p0} \left[ \left(\frac{I_{DQ}}{I_{DSS}} \right)^{1/2} – 1 \right] = -4 \left[ \left(\frac{-8}{-10} \right)^{1/2} – 1 \right] = 0.422 \text{V}
With negligible gate current, KVL requires that V_{GG} = V_{GSQ} = 0.422 \text{V}.
(b) Applying KVL around the drain-source loop gives
V_{DSQ} = V_{DD} – I_{DQ}R_D = (-20) – (-8 × 10^{-3})(1.5 × 10^{3}) = -8 \text{V}