If R of 10 Ω connected across terminal A and B as in the following circuit what is the value of current?

(a) 2 A (b) 3.175 A (c) 2.075 (d) 1.175

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The given circuit can be represented as

\begin{gathered} \frac{V_{ A }}{10}+\frac{V_{ A }}{4}+\frac{V_{ A }-5}{5}+\frac{V_{ A }-50}{7}=0 \\ \frac{140 V_{ A }+350 V_{ A }+280 V_{ A }-1400+200 V_{ A }-10000}{1400}=0 \\ 970 V_{ A }=11400 V_{ A }=11.75 \\ I=\frac{11.75}{10}=1.175 A \end{gathered}

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