In an astable multivibrator if R2 = 60 kΩ, R1 = 40 kΩ, C1 = C2 = 2.9 nF, find its frequency and duty cycle.

Question

In an astable multivibrator if[latex]\ R_{2}[/latex] = 60 kΩ,[latex]\ R_{1}[/latex] = 40 kΩ,[latex]\ C_{1} = C_{2}[/latex] = 2.9 nF, find its frequency and duty cycle.

Accepted Answer

[latex]\ T_{2} = 0.69 R_{1}C_{1} = 0.69 × 40 × 10^{3} × 2.9 × 10^{−9}[/latex] = 80 μs = 0.08 ms

[latex]\ T_{1} = 0.69R_{2}C_{2} = 0.69 × 60 × 10^{3} × 2.9 × 10^{−9}[/latex] = 120 μs = 0.12 ms

[latex]\ T = T_{1} + T_{2}[/latex] = 0.08 + 0.12 = 0.2 ms [latex]\ f = \frac{1}{T}[/latex] = 5 kHz

Duty cycle =[latex]\frac{T_{1}}{T}=\frac{0.12 ms}{0.2 ms}[/latex] = 0.6

Chapter 7

Q. 7.6

Q. 7.6

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