# Question 11.5: In the circuit shown in Fig. 11.16(a), RL = R1 = 200 kΩ, R2 ......

In the circuit shown in Fig. 11.16(a),$\ R_{L} = R_{1}$ = 200 kΩ,$\ R_{2}$ = 100 kΩ and the signal has a peak value of 10 V. Find (a) A (b)$\ V_{C(min)}$ (c)$\ V_{n(min)}$ (d)$\ R_{i}$

Step-by-Step
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(a)
$\ A = \frac{α}{1 + α(R_{1}/2R_{L})}$

$\ α = \frac{ R_{2}}{R_{1} + R_{2}}= \frac{100}{200 + 100} = \frac{1}{ 3}$                                                                                             $\frac{R_{1}}{2R_{L}} = \frac{200}{2 × 200} = \frac{1}{2}$

Therefore,

$\ A = \frac{(1/3)}{1 + ((1/3) × (1/2))} = \frac{(1/3)}{(7/6)} = \frac{1}{3} × \frac{6}{7} = \frac{2}{7}$  = 0.285

(b)
$\ V_{C(min)} = \frac{R_{2}}{R_{1}} × \frac{R_{3}}{R_{3} + 2R_{L}} V_{s}$

$\ R = \frac{R_{2}R_{1}}{ R_{2} + R_{1}}= \frac{100 × 200}{300} = \frac{200}{3}kΩ$

$\ R_{3} = R + R_{f} ≈ R$= 66.6 kΩ

$\ V_{C(min)} = \frac{100}{200} × \frac{66.6}{66.6 + 2 × 200} × 10$

$\ V_{C(min)}$= 0.71 V

(c)
$\ V_{n(min)} = \frac{−R_{2}}{R_{1}} × V_{s} = \frac{−100}{ 200} × 10$ = −5 V

(d) When the diodes are ON

$\ R_{i} = \frac{R_{L}R_{2}}{R_{2} + 2R_{L}} + \frac{R_{1}}{2}$

$\ = \frac{200 × 100}{100 + 400} + \frac{ 200}{2} = \frac{ 200}{5}$ + 100 = 40 + 100 = 140 kΩ

Question: 11.1

## In the circuit shown in Fig. 11.16(a), RL = R1 = 100 kΩ , R2 = 50 kΩ and the signal has a peak value of 20 V. Find (a) A (b) VC(min) (c) Vn(min) (d) Ri when the diodes are ON ...

(a) \ A = \frac{a}{1 + a\frac{R_{1}}{2R_{L}...
Question: 11.2

## For the four-diode gate shown in Fig. 11.20(a), RL = R2 = 100 kΩ and R1 = 1 kΩ, Rf = 25 Ω, Vs = 20 V. Calculate (a) A (b) V(min) (c) VC(min) (d) Vn(min) for V = V(min) ...

(a) We have: \ R = \frac{R_{1}R_{2}}{R_{1} ...
Question: 11.3

## For the four diode gate shown in Fig. 11.21(a), Vs = 20 V, RL = 200 kΩ , RC = 100 kΩ, Rf = 0.5 kΩ, R = Rs = 1 kΩ. Find Vn(min), A and VC(min). ...

(i) From Eq. (11.17), \ V_{n(min)} = V_{s}[...
Question: 11.4

## Consider the following situation in the FET series gate, Vs = ± 2 V, Rs = 100 Ω, RL = 10 kΩ. The FET has the following parameters: VGS(OFF)max = −10 V and RD(ON) = 20 Ω. Calculate the voltage levels of the control signal, ID, error due to RS and error due to RD(ON). ...

The control signal should have a value\ V_{...
Question: 11.6

## For the four-diode gate shown in Fig 11.20(a), RL = R2 = 50 kΩ and R1 = 1 kΩ, Rf = 25 Ω, Vs = 10 V. Calculate (a) A (b) V(min) (c) VC(min) (d) for V = V(min) ...

(a) We have \ R = \frac{R_{2}R_{1}}{R_{2} +...
The control signal should have a value\ V_{...