Chapter 1
Q. 1.P.52
Maximum power delivered to R in Ω by a 20 V DC source with 5 Ω internal resistance is
Step-by-Step
Verified Solution
We have
R=5 \Omega, I=\frac{20}{10}=2 A
So, the power delivered to R is
P_{ L }=I^2 R=4 \times 5=20 W
Maximum power delivered to R in Ω by a 20 V DC source with 5 Ω internal resistance is
We have
R=5 \Omega, I=\frac{20}{10}=2 A
So, the power delivered to R is
P_{ L }=I^2 R=4 \times 5=20 W