Norton equivalence of the network `X’ to the left of AB is a current source IN = 5 A from B to A, RN = 3 Ω and current through R when it is connected across AB = 2 A. What is the value of resistance R?

Question

Norton equivalence of the network `X’ to the left of AB is a current source [latex] I_{ N }= [/latex] 5 A from B to A, [latex] R_{ N }= [/latex] 3 Ω and current through R when it is connected across AB = 2 A. What is the value of resistance R?

Accepted Answer

The resistance is given by

[latex] \begin{gathered} \frac{5 imes 3}{3+R}=2 \Rightarrow \frac{15}{3+R}=2 \ 5+6+2 R \Rightarrow 2 R=9 \Rightarrow R=\frac{9}{2}=4.5 \Omega \end{gathered} [/latex]

Ans. (4.5)

Chapter 1

Q. 1.P.47

Q. 1.P.47

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