Chapter 7
Q. 7.Q.11
Oil with a specific weight of 53 lb/ft³ is exiting from a pipe whose center line is 17 ft below the surface of the oil. What is the velocity of the oil from the pipe if there is 1.5 ft head loss in the exit pipe?
Step-by-Step
Verified Solution
\begin{matrix} \frac{p_{1}}{\gamma}+\frac{V_{1}^{2}}{2g}+Z_{1}=\frac{p_{2}}{\gamma}+\frac{V_{2}^{2}}{2g}+Z_{2} \\ 0+0+17=0+V_{2}^{2}/2g+1.5 \\ V_{2} = √15.5 × 2 × 32.2 = 31.6 \ ft/s \end{matrix}