Holooly Plus Logo

Question 2.SP.2: The specific weight of water at ordinary pressure and temper......

The specific weight of water at ordinary pressure and temperature is 9.81 \mathrm{kN} / \mathrm{m}^3 . The specific gravity of mercury is13.56. Compute the density of water and the specific weight and density of mercury.

Step-by-Step
The 'Blue Check Mark' means that this solution was answered by an expert.
Learn more on how do we answer questions.
\begin{aligned}\rho_{\text {water }} & =\frac{9.81 \mathrm{kN} / \mathrm{m}^3}{9.81 \mathrm{~m} / \mathrm{s}^2}=1.00 \mathrm{Mg} / \mathrm{m}^3=1.00 \mathrm{~g} / \mathrm{mL} & &   \\\gamma_{\text {mercury }} & =s_{\text {mercury }} \gamma_{\text {water }}=13.56(9.81)=133.0 \mathrm{kN} / \mathrm{m}^3    \\\rho_{\text {mercury }} & =s_{\text {mercury }} \rho_{\text {water }}=13.56(1.00)=13.56 \mathrm{Mg} / \mathrm{m}^3 \end{aligned}

Related Answered Questions

Question: 2.SP.10

Verified Answer:

Table A.1 at 10^{\circ} \mathrm{C}: \quad \...
Question: 2.SP.11

Verified Answer:

From Appendix A, Table A.3, the pressure of the st...