Chapter 1
Q. 1.P.44
Thevenin equivalent resistance R_{ Th } for the given network is
Step-by-Step
Verified Solution
From the given circuit, 2 A source is open circuit and 2 V source is short circuit.
R_{ Th }=16+\frac{12 \times 4}{16}=\frac{64+12}{4}=16+3=19 \Omega
