Water in an open channel flows at a depth of 3.5 m, where the average velocity is 3 m/s. The bed is 12 m above the datum line. Find the total energy in pressure head per unit weight of water at the cross-section at any section.

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The total energy or pressure head of liquid in open channel by Bernoulli’s equation is:

H=z+y+\frac{V^{2} }{2g} (i)

Substituting the values of datum head, depth and velocity in Eq. (i), we have

H=12+3.5+\frac{3^{2} }{2×9.81}

H =15.95 m of water