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## Q. 5.2

A spectrophotometric method for the quantitative determination of $Pb^{2+}$ levels in blood yields an $S_{stand}$ of 0.474 for a standard whose concentration of lead is 1.75 ppb. How many parts per billion of $Pb^{2+}$ occur in a sample of blood if $S_{samp}$ is 0.361?

## Verified Solution

Equation 5.3 allows us to calculate the value of k for this method using the data for the standard

$k=\frac{S_{stand}}{C_S} = \frac{0.474}{1.75 ppb} = 0.2709 ppb^{-1}$            (a)

Once k is known, the concentration of $Pb^{2+}$ in the sample of blood can be calculated using equation 5.4

$C_A=\frac{S_{samp}}{k} =\frac{0.361}{0.2709 ppb^{-1}} =1.33 ppb$