Chapter 2
Q. 2.2
A thermometer reads 32°F when placed in melting ice and 212°F when placed in boiling water. What will it read when the measured temperature is 290 K ?
Step-by-Step
Verified Solution
Let t = ax + b
So that 32 = ax_i+ b
212 = ax_s+ b
Which gives, a=\frac{180}{x_s-x_i}, b=32-180\left[\frac{x_i}{x_s-x_i}\right]
t^{\circ} F =180\left[\frac{x-x_i}{x_s-x_i}\right]+32
Also, t^{\circ} C =100\left[\frac{x-x_i}{x_s-x_i}\right]
\therefore t°F = 1.8 t°C + 32
Now t°C = 290 – 273.15 = 16.85
\therefore t°F = 1.8 × 16.85 + 32 = 62.33