## Textbooks & Solution Manuals

Find the Source, Textbook, Solution Manual that you are looking for in 1 click.

## Tip our Team

Our Website is free to use.
To help us grow, you can support our team with a Small Tip.

## Holooly Tables

All the data tables that you may search for.

## Holooly Help Desk

Need Help? We got you covered.

## Holooly Arabia

For Arabic Users, find a teacher/tutor in your City or country in the Middle East.

Products

## Textbooks & Solution Manuals

Find the Source, Textbook, Solution Manual that you are looking for in 1 click.

## Holooly Arabia

For Arabic Users, find a teacher/tutor in your City or country in the Middle East.

## Holooly Help Desk

Need Help? We got you covered.

## Q. 17.2

Absorbance, Transmittance, and Beer’s Law

Find the absorbance and transmittance of a 0.002 40 M solution of a substance with a molar absorptivity of 313 $M^{−1} cm^{−1}$ in a cell with a 2.00-cm pathlength.

## Verified Solution

Equation 17-6 gives us the absorbance.

$A = εbc = (313 M^{−1} cm^{−1})(2.00 cm)(0.002 40 M) = 1.50$

Transmittance is obtained from Equation 17-5 by raising 10 to the power equal to the expression on each side of the equation:

$A = log(\frac{P_0}{P} )= – log T$                (17-5)

$\log T = −A$

$T = 10^{\log T} = 10^{−A} = 10^{−1.50} = 0.031 6$

Just 3.16% of the incident light emerges from this solution.

Test Yourself     The transmittance of a 0.010 M solution of a compound in a 0.100-cm-pathlength cell is T = 8.23%. Find the absorbance (A) and the molar absorptivity (ε).
(Answer: 1.08, 1.08 × $10^{3} M^{−1} cm^{−1}$)

If x = y, $10^{x} = 10^{y}$.