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## Q. 7.2

An amplifier produces a one-sided noise spectrum given by $S_{noise}( f ) = 5 × 10^{−16} V^2/Hz$. Determine the total output noise in a bandwidth of 1 MHz.

## Verified Solution

We have

$P_{noise} =\int_{0}^{1 MHz}{S_{noise}(f)d f}$                                 (7.14)

$= 5 × 10^{−10} V^2$                                                    (7.15)

Note that the total integrated noise is measured in $V^2$ and not in $V^2/Hz$. This noise power corresponds to an rms voltage of $\sqrt{5 × 10^{−10} V^2} = 22.4 μV$.