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An amplifier produces a one-sided noise spectrum given by S_{noise}( f ) = 5 × 10^{−16} V^2/Hz. Determine the total output noise in a bandwidth of 1 MHz.
We have
P_{noise} =\int_{0}^{1 MHz}{S_{noise}(f)d f} (7.14)
= 5 × 10^{−10} V^2 (7.15)
Note that the total integrated noise is measured in V^2 and not in V^2/Hz. This noise power corresponds to an rms voltage of \sqrt{5 × 10^{−10} V^2} = 22.4 μV.