# Question 2.48: An engine working on Carnot cycle absorbs Q1 units of heat f...

An engine working on Carnot cycle absorbs Q_1 units of heat from a source at T_1 and rejects Q_2 units of heat to a sink at T_2 . The temperature of the working fluid is \theta_1 and \theta_2 , where \theta_1<T_1 and \theta_2>T_2.

If \theta_1=T_1-k Q_1 \text { and } \theta_2=T_2+k Q_2

where k is constant, then show that efficiency of the engine is given by :

\eta=1-\frac{T_2}{T_1-2 k Q_1}

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