Chapter 2
Q. 2.11
Calculate the work done when the volume changes from 5 m³ to 10 m³ in a non – flow quasi – static process in which pressure is given by :
p = (5V – 5) bar.
Step-by-Step
Verified Solution
Work done,
\begin{aligned}W_{1 \cdot 2} &=\int p \cdot d V=\int_5^{10}(5 V-5) \times 10^5 d V \\&=10^5\left|2.5 V^2-5 V\right|_5^{10}=16250 \ kJ\end{aligned}