Question 4.9: Calculating Molarity from Mass and Volume A sample of NaNO3 ...
Calculating Molarity from Mass and Volume
A sample of NaNO_3 weighing 0.38 g is placed in a 50.0-mL volumetric flask. The flask is then filled with water to the mark on the neck, dissolving the solid. What is the molarity of the resulting solution?
PROBLEM STRATEGY
To calculate the molarity, you need the moles of solute. Therefore, you first convert grams NaNO_3 to moles. The molarity equals the moles of solute divided by the liters of solution.
The "Step-by-Step Explanation" refers to a detailed and sequential breakdown of the solution or reasoning behind the answer. This comprehensive explanation walks through each step of the answer, offering you clarity and understanding.
Our explanations are based on the best information we have, but they may not always be right or fit every situation.
Our explanations are based on the best information we have, but they may not always be right or fit every situation.
The blue check mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.
Learn more on how we answer questions.
Related Answered Questions
Question: 4.3
Verified Answer:
a. The formulas of the compounds are NaCl and [lat...
Question: 4.2
Verified Answer:
a. According to the solubility rules presented in ...
Question: 4.14
Verified Answer:
The calculation is as follows:
4.47 \times...
Question: 4.13
Verified Answer:
The calculation is as follows:
35.0 \times...
Question: 4.12
Verified Answer:
Following Example 3.7, you obtain the mass percent...
Question: 4.11
Verified Answer:
You know the final volume (100.0 mL), final concen...
Question: 4.10
Verified Answer:
Here is the calculation. (The molar mass of NaOH i...
Question: 4.1
Verified Answer:
a. According to Rule 3 in Table 4.1, most compound...
Question: 4.8
Verified Answer:
Identify the oxidation states of the elements:
[la...
Question: 4.5
Verified Answer:
The salt consists of the cation from the base ([la...