Using the conversion factors listed inside the front cover, we obtain

5000\:lb/in.^{2} = 5000\frac{\cancel{lb}}{\cancel{in.}^{2}}×\frac{4.448N}{1.0\:\cancel{lb}}×\left(\frac{39.37\cancel{in}}{1.0\:m} \right)^{2} \\ =34.5\times 10^{6}\:N/m^{2}= 34.5\: MPa