## Textbooks & Solution Manuals

Find the Source, Textbook, Solution Manual that you are looking for in 1 click.

## Tip our Team

Our Website is free to use.
To help us grow, you can support our team with a Small Tip.

## Holooly Tables

All the data tables that you may search for.

## Holooly Help Desk

Need Help? We got you covered.

## Holooly Arabia

For Arabic Users, find a teacher/tutor in your City or country in the Middle East.

Products

## Textbooks & Solution Manuals

Find the Source, Textbook, Solution Manual that you are looking for in 1 click.

## Holooly Arabia

For Arabic Users, find a teacher/tutor in your City or country in the Middle East.

## Holooly Help Desk

Need Help? We got you covered.

## Q. 16.4

Coulometric Titration

A 2.000-mL volume containing 0.611 3 mg of cyclohexene/mL is to be titrated in Figure 16-8. How much time is required for titration at a constant current of 4.825 mA? ## Verified Solution

The moles of cyclohexene are

$\frac{(200 mL)(0.611 3 mg/mL)}{(82.146 mg/mmol)} = 0.014 88$ mmol

$2Br^{−} → Br_{2} + 2e^{−}$          (16-10) In Reactions 16-10 and 16-11, each mole of cyclohexene requires 1 mol of $Br_{2}$, which requires 2 mol of electrons. For 0.014 88 mmol of cyclohexene to react, 0.029 76 mmol of electrons must flow. From Equation 16-3,

$Moles of e^{−} = \frac{I · t}{F} ⇒ t = \frac{(moles of e^{−})F}{I}$

$t = \frac{(0.029 76 × 10^{−3} mol)(96 485 C/mol)}{(4.825 × 10^{−3} C/s)} = 595.1$ s

It will require just under 10 min to complete the reaction.

Test Yourself     How much time is required to titrate 1.000 mg of cyclohexene at 4.000 mA? (Answer: 587.3 s)