Products

Holooly Rewards

We are determined to provide the latest solutions related to all subjects FREE of charge!

Please sign up to our reward program to support us in return and take advantage of the incredible listed offers.

Enjoy Limited offers, deals & Discounts by signing up to Holooly Rewards Program

Holooly Ads. Manager

Advertise your business, and reach millions of students around the world.

Holooly Tables

All the data tables that you may search for.

Holooly Arabia

For Arabic Users, find a teacher/tutor in your City or country in the Middle East.

Holooly Sources

Find the Source, Textbook, Solution Manual that you are looking for in 1 click.

Holooly Help Desk

Need Help? We got you covered.

Chapter 2

Q. 2.3

Determine the forces produced by the applied loads in the members of the truss shown in Figure 2.13.

Determine the forces produced by the applied loads in the members of the truss shown in Figure 2.13.

Step-by-Step

Verified Solution

The support reactions are calculated as shown. By inspection, the force in the vertical web members is obtained directly. Thus, the force in member 23 is given as:

\begin{aligned}P_{23} &=W_{3} \\&=10 \text { kips … tension } \\P_{45} &=0\end{aligned}

The force in the diagonal web member 12 is given by the magnitude of the shear force in the first panel multiplied by the coefficient l/h. Thus, the force in member 12 is:

\begin{aligned}P_{12} &=V_{1} \times l / h \\&=15 \times 14.14 / 10 \\&=21.21  \text{kips… compression }\end{aligned}

The force in the diagonal web member 25 is given by the magnitude of the shear force in the second panel multiplied by the coefficient l/h. Thus, the force in member 25 is:

\begin{aligned}P_{25} &=\left(V_{1}-W_{3}\right) \times l / h \\&=5 \times 14.14 / 10 \\&=7.07 \text { kips … tension }\end{aligned}

The force in the bottom chord member 13 is given by the magnitude of the moment at node 2 multiplied by the coefficient 1/h. Thus, the force in member 13 is:

\begin{aligned}P_{13} &=M_{2} \times 1 / h \\&=V_{1} \times a \times 1 / h \\&=150 \times 1 / 10 \\&=15 \text { kips …tension }\end{aligned}

Similarly, the force in the bottom chord member 35 is given by the magnitude of the moment at node 2 multiplied by the coefficient 1/h. Thus, the force in member 35 is:

\begin{aligned}P_{35} &=M_{2} \times 1 / h \\&=V_{1} \times a \times 1 / h \\&=150 \times 1 / 10 \\&=15 \text { kips … tension }\end{aligned}

The force in the top chord member 24 is given as the magnitude of the moment at node 5 multiplied by the coefficient 1/h. Thus, the force in member 24 is:

\begin{aligned}P_{24} &=M_{5} \times 1 / h \\&=\left(V_{1} \times 2 a-W_{3} \times a\right) \times 1 / h \\&=(300-100) \times 1 / 10 \\&=20 \text { kips … compression }\end{aligned}