Chapter 7
Q. 7.2
Draw the Lewis structures of {NO _{2}}^{- } and N _{2} .
STRATEGY
Follow the steps outlined in Figure 7.3.

Step-by-Step
Verified Solution
Skeleton for {NO _{2}}^{- } [O–N–O]^{-}
VE 2(6 (for O)) + 5 (for N) + 1(-1 charge) = 18
AE AE = VE – 2(bonds) = 18 – 2(2 bonds) = 14
NE 2(6 (for each O)) + 4 (for N) = 16
AE = NE ? No; 2 electrons short
Convert a single bond to a double bond.<\p>
Lewis structure \left[:\overset{..}{\underset{..}{\overset{..}{O} }-\overset{..}{N}= \overset{..}{O}: } \right] ^{-}
Skeleton for N _{2} N–N
VE 2(5 (for each N)) = 10
AE AE = VE – 2(bonds) = 10 – 2(1 bond) = 8
NE 2 × 6 (for each N to have an octet) = 12
AE= NE ? No; 4 electrons short
Convert a single bond to a triple bond.
Lewis structure :N\equiv N:
END POINT
For the Lewis structure of NO^{- } _{2} , it does not matter which single bond you convert to a double bond. We will talk about this in more detail when we discuss resonance forms.