Half-Life Molecular iodine dissociates at 625 K with a first-order rate constant of 0.271 s-1.What is the half-life of this reaction?

Question

Half-Life

Molecular iodine dissociates at 625 K with a first-order rate constant of 0.271 s[latex]^{-1}[/latex].What is the half-life of this reaction?

Accepted Answer

Since the reaction is first order, the half-life is given by Equation 13.19.

[latex]t_{1/2}=\frac{0.693}{k}[/latex] [13.19]

Substitute the value of k into the expression and calculate t[latex]_{1/2}[/latex].

[latex]t_{1/2}=\frac{0.693}{k}[/latex]
= [latex]\frac{0.693}{0.271/s}[/latex] = 2.56 s

Subscribe $4.99/month