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## Q. 13.6

Half-Life

Molecular iodine dissociates at 625 K with a first-order rate constant of 0.271 s$^{-1}$.What is the half-life of this reaction?

## Verified Solution

 Since the reaction is first order, the half-life is given by Equation 13.19. $t_{1/2}=\frac{0.693}{k}$    [13.19] Substitute the value of k into the expression and calculate t$_{1/2}$. $t_{1/2}=\frac{0.693}{k}$ = $\frac{0.693}{0.271/s}$ = 2.56 s