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Chapter 13

Q. 13.6

Half-Life

Molecular iodine dissociates at 625 K with a first-order rate constant of 0.271 s^{-1}.What is the half-life of this reaction?

Step-by-Step

Verified Solution

Since the reaction is first order, the half-life is given by Equation 13.19.

t_{1/2}=\frac{0.693}{k}    [13.19]

Substitute the value of k into the expression and calculate t_{1/2}.

t_{1/2}=\frac{0.693}{k}
= \frac{0.693}{0.271/s} = 2.56 s