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## Q. 5.2

Hurricane Irma in 2017 was one of the most destructive hurricanes in recent years, affecting the Caribbean, Cuba, U.S. Virgin Islands, and Florida, in particular. The lowest pressure recorded for Hurricane Irma was 691 mmHg. What was the pressure in kPa?

Strategy Here we are asked to convert mmHg to kPa. Because

$1 atm = 1.01325 \times 10^{5} Pa = 760 mmHg$

the conversion factor we need is

$\frac{1.01325 \times 10^{5} Pa}{760 mmHg}$

## Verified Solution

The pressure in kPa is

pressure$=691 \cancel{mm Hg} \times \frac{1.01325 \times 10^{5} Pa}{760 \cancel{mm Hg} }$

=$9.21 \times 10^{4} Pa$

.=92.1  KPa