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## Q. 2.6

Resolve the force $F _2$ into components acting along the u and v axes and determine the magnitudes of the components.

## Verified Solution

$\frac{F_{2 u}}{\sin 45^{\circ}}=\frac{500}{\sin 70^{\circ}}$

$F_{2 u}=376 N$

$\frac{F_{2 v}}{\sin 65^{\circ}}=\frac{500}{\sin 70^{\circ}}$

$F_{2 v}=482 N$