Question 2.9: Tensile stresses of 160 MPa and 40 MPa are acting on two per...

Tensile stresses of 160 MPa and 40 MPa are acting on two perpendicular planes in a body. Determine the location of a plane on which the resultant stress is most inclined to its normal.

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Question: 2.22

Figure 2.30(a) shows an element under axial stress 20 MPa and 50 MPa along with shear stress 40 MPa in x-y plane. Determine the state of stress in x’ – y’ plane at 30° counter-clockwise to x-y plane. ...

Equation (2.11b) can be used to cal-culate stresse...
Question: 2.21

Write a computer program to calculate normal and shear stress on any inclined plane. It should calculate principal stresses and their location. Input data for the program will be the direct and shear stresses on two mutually perpendicular planes (σx, σy, τxy) and the angle of the inclined plane. ...

The following computer program in Qbasic will solv...
Question: 2.20

Tensile stresses of 100 MPa and 50 MPa are acting on two perpendicular planes in a body. Determine the resultant stress inclined at 35° to the major principal plane using stress ellipsoid. ...

Draw two circles corresponding to the principal st...
Question: 2.19

Figure 2.28 shows the state of stress at a point. Determine the stress tensor on x’y’z’ reference frame rotated such that x’-axis makes equal angle with x, y, z directions in first quadrant and y’-axis makes 60° with x-axis. ...

Using simpler notations for direction cosines, let...
Question: 2.18

Figure 2.28 shows the state of stress at a point. Determine the principal normal and shear stresses and the orientation at which they act. Also determine the octahedral normal and shear stresses. ...

Stress tensor, \left[\tau _{ i j}\right]=\b...
Question: 2.17

Solve Example 2.16 if the rotation of xyz reference is 30° clockwise. ...

Direction cosine matrix for transformation (Fig. 2...
Question: 2.16

he state of stress at a point in xyz reference is as follows. τ = |80 -60 0 -60 -40 0 0 0 40|MPa Determine the stress tensor in the direction x’y’z’ by rotating xyz through 30° anticlockwise about z-direction as shown in Fig. 2.26. ...

Direction cosines, c_{x^{\prime} x}=\cos 30...
Question: 2.15

A cantilever 50 mm diameter is to carry an axial load 50 kN at an eccentricity of 5 mm below horizontal diameter in the vertical plane of symmetry along with a torque of 1.5 x 10^6 N mm as shown in Fig. 2.24. Calculate the stresses on a plane, normal of which is inclined at 30° clockwise to axis ...

Consider an element at a lowermost point P. Direct...
Question: 2.14