# Question 29.2: The Henry’s law constant for oxygen dissolved in water is 4....

The Henry’s law constant for oxygen dissolved in water is $4.06 \times 10^{9} \mathrm{~Pa} /\left(\mathrm{mol}\right.$ of $\mathrm{O}_{2}$ per total mol of solution) at $293 \mathrm{~K}$. Determine the solution concentration of oxygen in water that is exposed to dry air at $1.013 \times 10^{5} \mathrm{~Pa}$ and $293 \mathrm{~K}$.

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Question: 29.4

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