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Chapter 3

Q. 3.7

The molar mass of acetic acid, as determined with a mass spectrometer, is about 60 g/mol. Using that information along with the simplest formula found in Example 3.6, determine the molecular formula of acetic acid.

ANALAYSIS
simplest formula (CH_{2}O)
MM_{a}: actual molar mass (60 g/mol)
Information given:
molecular formula Asked for:

STRATEGY

1. Determine the molar mass of the simplest formula, MM_{s}
2. Find the ratio

\frac{\text{ actual molar mass}}{\text{simplest formula molar mass}} = \frac{MM_{a}}{MM_{s}}

3. To get the molecular formula, multiply all subscripts in the simplest formula by the ratio.

Step-by-Step

Verified Solution

12.01 g C + 2(1.008) g H + 16.00 g O = 30.03 g CH_{2}O/mol 1.MM_{s}
\frac{MM_{a}}{MM_{s}} = \frac{60}{30.03} = 2 2. ratio
C_{1×2}H_{2×2}O_{1×2} The molecular formula of acetic acid is C_{2}H_{4}O_{2}. 3. molecular formula