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t = a ln p + b

At ice point, 0 = a ln 2 + b

At steam point, 100 = a ln 8 + b

Which gives, a=\frac{100}{\ln 4}=72.135

b = – 50

t = 72.135 ln p – 50

At p = 4, t = 72.135 ln 4 – 50 = 50°C