Chapter 4
Q. 4.13
The yield, in grams, of a dye manufacturing process is normally distributed with mean 1500 and standard deviation 50. The yield of a particular run is 1568 grams. Find the z-score.
Step-by-Step
Verified Solution
The quantity 1568 is an observation from a normal population with mean μ = 1500 and standard deviation σ = 50. Therefore
z = \frac{1568 – 1500}{50}= 1.36