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Chapter 4

Q. 4.13

The yield, in grams, of a dye manufacturing process is normally distributed with mean 1500 and standard deviation 50. The yield of a particular run is 1568 grams. Find the z-score.

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Verified Solution

The quantity 1568 is an observation from a normal population with mean μ = 1500 and standard deviation σ = 50. Therefore

z = \frac{1568 – 1500}{50}

= 1.36