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## Q. 4.13

The yield, in grams, of a dye manufacturing process is normally distributed with mean 1500 and standard deviation 50. The yield of a particular run is 1568 grams. Find the $z$-score.

## Verified Solution

The quantity 1568 is an observation from a normal population with mean μ = 1500 and standard deviation σ = 50. Therefore

$z = \frac{1568 – 1500}{50}$

= 1.36