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## Q. 7.2

Two long parallel wires are at a distance of 15 cm as shown in Fig. 7.4. If $I_{1}$ = 50 A, what should be the value and direction of the current $I_{2}$ such that the magnetic field intensity at point P is zero? ## Verified Solution

At point P

$H_{1} (I_{1}) = \frac{50}{2π (15 + 10) × 10^{-2} }$ A/m

$H_{2} (I_{2}) = \frac{I_{2}}{2π × 10 × 10^{-2} }$ A/m

For net H at P to be zero

$H_{1} + H_{2}$ = 0       or      $H_{2} = -H_{1}$

or               $\frac{I_{2}}{2π × 10 × 10^{-2} } = \frac{50}{2π × 10 × 10^{-2}}$

or

$I_{2} = – 50 × \frac{10}{25}$ = –20 A (in opposite direction to $I_{1}$)