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## Q. 1.20

Two particles have a mass of 8 kg and 12 kg, respectively. If they are 800 mm apart, determine the force of gravity acting between them. Compare this result with the weight of each particle.

## Verified Solution

$F=G \frac{m_1 m_2}{r^2}$

$\text { Where } G=66.73\left(10^{-12}\right) m ^3 /\left( kg \cdot s ^2\right)$

$F=66.73\left(10^{-12}\right)\left[\frac{8(12)}{(0.8)^2}\right]=10.0\left(10^{-9}\right) N =10.0 nN$

$W_1=8(9.81)=78.5 N$

$W_2=12(9.81)=118 N$