# Question 4.10: Using Molarity as a Conversion Factor An experiment calls fo...

Using Molarity as a Conversion Factor

An experiment calls for the addition to a reaction vessel of 0.184 g of sodium hydroxide, NaOH, in aqueous solution. How many milliliters of 0.150 M NaOH should be added?

PROBLEM STRATEGY

You first need to convert grams NaOH to moles NaOH, because molarity relates moles of solute to volume of solution. Then, you convert moles NaOH to liters of solution, using the molarity as a conversion factor. Here, 0.150 M means that 1 L of solution contains 0.150 moles of solute, so the conversion factor is:

$\frac{1 L soln}{\underbrace{0.150 mol NaOH}_{\begin{matrix} _{Converts} \\ _{mol NaOH to L soln} \end{matrix} } }$
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