Question 8.44: A 400 MVA, 22 kV synchronous generator is tested for OCC and...

A 400 MVA, 22 kV synchronous generator is tested for OCC and SCC. The following data are obtained from these characteristics extrapolated where needed.

I_{f}=1120 A , \quad V_{O C}=22 kV , \quad I_{S C}=13.2 kA

At I_{f} corresponding to I_{SC} = I_{rated} it is found that V_{OC} (air-gap line) = 24.2 kV (line).

(a) Determine X_{s} (saturated) in ohms and in pu.

(b) Determine SCR.

(c) Determine X_{s} (unsaturated) and I_{f} corresponding to V_{OC} = 22.4 kV on air gap line.

(d) The generator when operating on no-load rated terminal voltage, find the value of the generator current if it is short circuited.

The Blue Check Mark means that this solution has been answered and checked by an expert. This guarantees that the final answer is accurate.
Learn more on how we answer questions.

Base                              ( MVA )_{B}=400,( kV )_{B}=22 (line) or 12.7 (phase)

I_{B}=\frac{400}{22 \sqrt{3}}=10.49 kA

 

( Ohm )_{B}=\frac{22 \sqrt{3}}{10.49}=1.21 \Omega

(a)                                          I_{f} = 1120 A

 

V_{O C}=V_{\text {rated }}=\frac{22}{\sqrt{3}}=12.7 kV (phase)

 

I_{S C}=13.2 kA

Then                                   X_{s}( sat )=\frac{12.7}{13.2}=0.962 \Omega

Or                                                \frac{0.962}{1.21}=0.795 pu

(b)                                   S C R=\frac{1}{X_{s}( sat )( pu )}=\frac{1}{0.795}=1.258

(c)                             I_{S C}=I_{ rated }=10.49 kA

 

V_{O C} \text { (air gap line) }=24.2 kV (line)

= 13.97 kV (phase)

X_{s} \text { (unsat) }=\frac{13.97}{10.49}=1.33 \Omega=\frac{1.33}{1.21}=1.1 pu

For finding I_{f}                  SCR =\frac{o f^{\prime}}{o f^{\prime \prime}}        (Fig. 8.15)

1.258=\frac{o f^{\prime}}{1120}

Or                                    I_{f}=o f^{\prime}=1120 \times 1.258=1409 A

8 44

Related Answered Questions