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Q. 3.2

A charged particle having mass equal to 1000 times of an electron and a charge same as that of an electron is accelerated through a potential difference of 1000 V. Calculate the velocity attained by the charged particle and kinetic energy in terms of electron volts and joules.

Verified Solution

The mass of the charged particle = 1000 times the mass of an electron

$= 1000 × 9.1 × 10^{–31} = 9.1 × 10^{–28} kg$

The charge of the particle              $= 1.602 × 10^{–19} C$

Therefore, the velocity,                  $v=\sqrt{\frac{2qV}{m} }=\sqrt{\frac{2\times 1.602\times 10^{-19}\times 1000 }{9.1\times 10^{-28} } }=0.596\times 10^{6}ms^{-1}$

Kinetic energy                                  = q × V

$=1.602 × 10^{–19} × 1000 = 1.6 × 10^{–16} J = 1000 eV$