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## Q. 3.2

A charged particle having mass equal to 1000 times of an electron and a charge same as that of an electron is accelerated through a potential difference of 1000 V. Calculate the velocity attained by the charged particle and kinetic energy in terms of electron volts and joules.

## Verified Solution

The mass of the charged particle = 1000 times the mass of an electron

$= 1000 × 9.1 × 10^{–31} = 9.1 × 10^{–28} kg$

The charge of the particle              $= 1.602 × 10^{–19} C$

Therefore, the velocity,                  $v=\sqrt{\frac{2qV}{m} }=\sqrt{\frac{2\times 1.602\times 10^{-19}\times 1000 }{9.1\times 10^{-28} } }=0.596\times 10^{6}ms^{-1}$

Kinetic energy                                  = q × V

$=1.602 × 10^{–19} × 1000 = 1.6 × 10^{–16} J = 1000 eV$