A transformer on no-load has a core-loss of 50 W,draws a current of 2 A(rms)and has an induced emf of 230 V(rms).Determine the no-load power factor,core-loss current and magnetizing current.Also calculate the no-load circuit parameters of the transformer.Neglect winding resistance and leakage flux.

Question

Accepted Answer

Power factor,
[latex]\cos heta _{0} =\frac{50}{2 imes 230}=0.108[/latex] lagging;
[latex] heta _{0} =83.76°[/latex]
Magnetizing current,
[latex]I_{m} =I_{0} \sin heta _{0}=2\sin \left(\cos ^{-1} 0.108 ight) =1.988[/latex] A
Since [latex] heta _{0}\approx 90°[/latex], there is hardly any difference between the magnitudes of the exciting current and its magnetizing component.
Core-loss current, [latex]I_{i} = I_{0}\cos heta _{0}=2 imes 0.108=0.216[/latex] A
In the no-load circuit model of Fig.3.7 core loss is given by
[latex]G_{i} V_{1} ^{2} =P_{i}[/latex]
or [latex] G_{i}=\frac{P_{i}}{V_{1} ^{2}} =\frac{50}{\left(230 ight) ^{2} } =0.945 imes 10^{-3} \mho [/latex]
Also [latex] I_{m} =B_{m}V_{1}[/latex]
or [latex] B_{m}=\frac{I_{m} }{V_{1}} =\frac{1.988}{230} =8.64 imes 10^{-3} \mho[/latex]

Q. 3.1

Step-by-Step

Verified Answer

This Problem has been solved.

Unlock this answer and thousands more Step-by-Step Solved solutions by becoming a member.

Cancel Anytime..

Already have an account?

Q. 3.1

Step-by-Step

Verified Answer

This Problem has been solved. Unlock this answer and thousands more Step-by-Step Solved solutions by becoming a member.

Cancel Anytime..

Already have an account?

This Problem has been solved.

Unlock this answer and thousands more Step-by-Step Solved solutions by becoming a member.