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## Q. 1.1.8

Consider the signal $s(t)=m(t) \cos \left(2 \pi f_{c} t\right)+\hat{m}(t)\sin \left(2 \pi \cdot f_{c} \cdot t\right)$ where $\hat{m}(t)$ denotes the Hilbert transform of m(t) and the bandwidth of m(t) is very small compared to $f_{c} .$. The signal s(t) is a

(A) high-pass signal

(B) low-pass signal

(C) band-pass signal

(D) double sideband suppressed carrier signal

## Verified Solution

Signal $s(t)=m(t) \cos \left(2 \pi f_{c} t\right)+\hat{m}(t) \sin \left(2 \pi f_{c} t\right)$ This is the equation of SSB-SC so it will look like band-pass signal.
Hence, the correct option is (C).