Consider the signal s(t) = m(t) cos (2π fct) + mˆ (t) sin (2π.fc.t) where mˆ (t) denotes the Hilbert transform of m(t) and the bandwidth of m(t) is very small compared to fc. The signal s(t) is a (A) high-pass signal (B) low-pass signal (C) band-pass signal (D) double sideband suppressed carrier signal

Question

Consider the signal [latex]s(t)=m(t) \cos \left(2 \pi f_{c} t\right)+\hat{m}(t)\sin \left(2 \pi \cdot f_{c} \cdot t\right)[/latex] where [latex]\hat{m}(t)[/latex] denotes the Hilbert transform of m(t) and the bandwidth of m(t) is very small compared to [latex]f_{c} .[/latex]. The signal s(t) is a

(A) high-pass signal

(B) low-pass signal

(C) band-pass signal

(D) double sideband suppressed carrier signal

Accepted Answer

Signal [latex]s(t)=m(t) \cos \left(2 \pi f_{c} t\right)+\hat{m}(t) \sin \left(2 \pi f_{c} t\right)[/latex] This is the equation of SSB-SC so it will look like band-pass signal.
Hence, the correct option is (C).

Q. 1.1.8

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