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Determine the load voltage { v }_{ L } in the circuit of Fig. 5.99.

Step-by-step

The first stage is an inverter. The output is

\mathrm{v}_{01}=-\frac{50}{10}(-1.8)+1.8=10.8 \mathrm{V}

The second stage is

{ v }_{ 2 } ={ v }_{ 01 }= 10.8V

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