Determine the static deflection of the spring in the system of Figure 2.6(a).
Chapter 2
Q. 2.3
Step-by-Step
Verified Solution
The FBDs of the system in its equilibrium position are shown in Figure 2.6(b). Summing forces to zero on the FBD of the left hand block \sum F=0 leads to
T_1+m_1g-k\Delta _s (a)
Summing moments about the center of the disk leads to \sum M_\omicron =0, as
m_2gr_2-\left(m_1g-k\Delta_s \right)r_1= 0 (b)
from which the static deflection is determined as
\Delta _s=\frac{m_1gr_1 – m_2gr_2}{kr_1} (c)
