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Determine the time needed for the load at B to attain a speed of 8 m/s , starting from rest, if the cable is drawn into the motor with an acceleration of 0.2 m/{s}^{2}.

Step-by-step

4 s_{B}+s_{A} =l
4 v_{B} =-v_{A}

4 a_{B}=-a_{A}
4 a_{B}=-0.2
a_{B}=-0.05 m/{s}^{2}

(+\downarrow)    v_{B}=\left(v_{B}\right)_{0}+a_{B} t
-8=0-(0.05)(t)
t=160 s

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