Products
Rewards 
from HOLOOLY

We are determined to provide the latest solutions related to all subjects FREE of charge!

Please sign up to our reward program to support us in return and take advantage of the incredible listed offers.

Enjoy Limited offers, deals & Discounts by signing up to Holooly Rewards Program

HOLOOLY 
BUSINESS MANAGER

Advertise your business, and reach millions of students around the world.

HOLOOLY 
TABLES

All the data tables that you may search for.

HOLOOLY 
ARABIA

For Arabic Users, find a teacher/tutor in your City or country in the Middle East.

HOLOOLY 
TEXTBOOKS

Find the Source, Textbook, Solution Manual that you are looking for in 1 click.

HOLOOLY 
HELP DESK

Need Help? We got you covered.

Chapter 5

Q. 5.1

Determining the amount of phases in carbon steel
Determine the amount of gamma and alpha phases in a 10-kg, 1040 steel casting as it is being cooled slowly to the following temperatures: (a) 1173 K, (b) 1001 K, and (c) 999 K.

Step-by-Step

Verified Solution

(a) Referring to Fig. 5.4b, we draw a vertical line at 0.40% C at 1173 K.
We are in the single-phase austenite region, so percent gamma is 100 (10 kg) and percent alpha is zero. (b) At 1001 K, the alloy is in the two-phase gamma-alpha field. When we draw the phase diagram in greater detail, we can find the weight percentages of each phase by the lever rule:

Percent alpha = \left\lgroup\frac{C_{\gamma }-C_{0}}{C_{\gamma }-C_{\alpha }} \right\rgroup 100=\left\lgroup\frac{0. 77-0.40}{0.77-0.022} \right\rgroup100 = 50 %, or 5 kg.

Percent gamma = \left\lgroup\frac{C_{0 }-C_{\alpha }}{C_{\gamma }-C_{\alpha }} \right\rgroup100=\left\lgroup\frac{0. 40-0.022}{0.77-0.022} \right\rgroup100 = 50 %, or 5 kg.

(c) At 999 K, the alloy will be in the two-phase alpha and Fe_{3}C region. No gamma phase will be present. Again, we use the lever rule to find the amount of alpha present:

Percent alpha =\left\lgroup\frac{6.67 – 0.40}{6.67 – 0.022} \right\rgroup ×100% =94% , or 9.4 kg.