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Find { i }_{ 0 } in the op amp circuit of Fig. 5.100.

Step-by-step

Let { v }_{ 1 } = output of the first op amp

{ v }_{ 2 }= input of the second op amp.

The two sub-circuits are inverting amplifiers

\begin{array}{l}\mathrm{v}_{1}=-\frac{100}{10}(0.6)=-6 \mathrm{V} \\\mathrm{v}_{2}=-\frac{32}{1.6}(0.4)=-8\mathrm{V}\\\mathrm{i}_{\mathrm{o}}=\frac{\mathrm{v}_{1}-\mathrm{v}_{2}}{20 \mathrm{k}}=-\frac{-6+8}{20 \mathrm{k}}=\underline{\mathbf{1 0 0} \mathbf{\mu} \mathbf{A}}\end{array}

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