Find the total resistance of the configuration in Fig. 6.6.
Chapter 6
Q. 6.3
Step-by-Step
Verified Solution
First the network is redrawn as shown in Fig. 6.7 to clearly demonstrate that all the resistors are in parallel
Applying Eq. (6.3) gives
R_T=\frac{1}{\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+\cdot \cdot \cdot +\frac{1}{R_N} } (6.3)
R_T=\frac{1}{\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}}=\frac{1}{\frac{1}{1\Omega }+\frac{1}{4\Omega }+\frac{1}{5\Omega } }\\[0.5cm] =\frac{1}{1S+0.25S+0.2S}=\frac{1}{1.45S}\cong 0.69\Omega
