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Chapter 8

Q. 8.7

For the gear train shown in Figure 8–42, if the input shaft rotates at 1750 rpm clockwise, compute the speed of the output shaft and its direction of rotation.

Step-by-Step

Verified Solution

We can find the output speed if we can determine the train value:
TV = n_A/n_D = input speed/output speed

Then
n_D = n_A/TV
But

TV=(VR_1)(VR_2)=\frac{N_B}{N_A} \frac{N_D}{N_C}=\frac{70}{20} \frac{54}{18}=\frac{3.5}{1} \frac{3.0}{1}=10.5

Now
n_D = n_A/TV = (1750 rpm)/10.5 = 166.7 rpm
Gear A rotates clockwise; gear B rotates counterclockwise.
Gear C rotates counterclockwise; gear D rotates clockwise.
Thus, the train in Figure 8–42 is a positive train.