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Q. 8.7

For the gear train shown in Figure 8–42, if the input shaft rotates at 1750 rpm clockwise, compute the speed of the output shaft and its direction of rotation.

Verified Solution

We can find the output speed if we can determine the train value:
$TV = n_A/n_D$ = input speed/output speed

Then
$n_D = n_A/TV$
But

$TV=(VR_1)(VR_2)=\frac{N_B}{N_A} \frac{N_D}{N_C}=\frac{70}{20} \frac{54}{18}=\frac{3.5}{1} \frac{3.0}{1}=10.5$

Now
$n_D = n_A/TV = (1750$ rpm$)/10.5 = 166.7$ rpm
Gear $A$ rotates clockwise; gear $B$ rotates counterclockwise.
Gear $C$ rotates counterclockwise; gear $D$ rotates clockwise.
Thus, the train in Figure 8–42 is a positive train.