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For the op amp circuit in Fig. 5.76, determine the value of  { v }_{ 2 } in order to make { v }_{ 0 } = -16.5 V.

Step-by-step

This is a summing amplifier.

v_{o}=-\left(\frac{R_{f}}{R_{1}} v_{1}+\frac{R_{f}}{R_{2}} v_{2}+\frac{R_{f}}{R_{3}} v_{3}\right)=-\left(\frac{50}{10}(2)+\frac{50}{20} v_{2}+\frac{50}{50}(-1)\right)=-9-2.5 v_{2}

Thus,

v_{o}=-16.5=-9-2.5 v_{2} \quad \longrightarrow \quad v_{2}=3 \mathrm{V}

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